Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char timer[15] = "";
    char lat[15] = "";
    char ns[2] = "";
    char lon[15] = "";
    char ew[2] = "";
    char *token;
    token = strtok(nmea,",");
    token = strtok(NULL, ",");
    if (token != NULL){
        strcpy(timer, token);
    }
    token = strtok(NULL, ",");
    token = strtok(NULL, ",");
    if (token != NULL){
        strcpy(lat, token);
    }
    token = strtok(NULL, ",");
    if (token != NULL){
        strcpy(ns, token);
    }
    token = strtok(NULL, ",");
    if (token != NULL){
        strcpy(lon, token);
    }
    token = strtok(NULL, ",");
    if (token != NULL){
        strcpy(ew, token);
    }
    printf ("Time: %c%c:%c%c:%c%c\n", timer[0], timer[1], timer[2], timer[3], timer[4], timer[5]);
    printf ("Latitude: %s %s\n", lat, ns);
    printf ("Longitude: %s %s", lon, ew);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E