Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char time[9]={0},lat[11]={0},lon[12]={0};
    for (int i=7,j=0;i<=12;i++){
        time[j]=*(nmea+i);
        if (j==1 || j==4)   time[++j]=':';
        j++;
    }

    for (int i=16,j=0;i<=25;i++){
        if (*(nmea+i)==',')
            lat[j]=' ';
        else    lat[j]=*(nmea+i);
        j++;
    }

    for (int i=27,j=0;i<=37;i++){
        if (*(nmea+i)==',')
            lon[j]=' ';
        else    lon[j]=*(nmea+i);
        j++;
    }


    printf("Time: %s\n",time);
    printf("Latitude: %s\n",lat);
    printf("Longitude: %s",lon);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E