Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>
#include <stdint.h>
#include <stdlib.h>

void parse_gprmc(char *nmea) {
    // Your logic here

    nmea += sizeof("$GPRMC,") - 1;

    uint32_t time = atoi(nmea);
    printf("Time: %02u:%02u:%02u\n", time / 10000, (time % 10000) / 100, time % 100);
    
    nmea += sizeof("hhmmss,S,") - 1;
    printf("Latitude: ");
    uint8_t tmp_delim = 0;
    for (;*nmea != '\0';++nmea) {
        if (*nmea == ',') {
            if (++tmp_delim == 2) {
                printf("\nLongitude: ");
            }
            else {
                printf(" ");
            }
        }
        else {
            printf("%c", *nmea);
        }
    }
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach