Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char fields[7][20];
    int field_index=0;
    int char_index=0;
    while(field_index<7)
    {
        if(*nmea ==',' || *nmea=='\0' || *nmea=='\n')
        {
            fields[field_index][char_index]='\0';
            field_index++;
            char_index=0;
            if (*nmea == '\0') break;
        }
        else
        {
            fields[field_index][char_index++]=*nmea;
        }
        nmea++;
    }
    char *time = fields[1];
    printf("Time: %c%c:%c%c:%c%c\n",
        time[0], time[1],
        time[2], time[3],
        time[4], time[5]);
    printf("Latitude: %s %s\n",  fields[3], fields[4]);
    printf("Longitude: %s %s\n", fields[5], fields[6]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E