Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char *field[7];
    int index = 0;

    char *token = strtok(nmea, ",");
    while(token != NULL && index < 7) {
        field[index] = token;
        token = strtok(NULL, ",");
        index++;
    }

    char *t = field[1];
    printf("Time: %.2s:%.2s:%.2s\n", t, t + 2, t + 4);

    printf("Latitude: %s %s\n", field[3], field[4]);
    printf("Longitude: %s %s\n", field[5], field[6]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E