Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char data[7][20]={0};
    int read = 0;
    int row = 0 ;
    int col = 0;
    while(nmea[read])
    {
        if(nmea[read] != ',')
        {
            data[row][col]=nmea[read];
            col++;
        }
        else
        {
            data[row][col] = '\0';
            col = 0;
            row++;
        }
        read++;
    }
    printf("Time: ");
    for(int i = 0 ;i < strlen(data[1]); i++)
    {
        printf("%c",data[1][i]);
        if(i % 2 != 0 && i < strlen(data[1])-1)
        {
            printf(":");
        }
    }
    printf("\n");
    printf("Latitude: %s %s\n",data[3],data[4]);
    printf("Longitude: %s %s\n",data[5],data[6]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E