Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) 
{
    int i,j;
    char time[50],lat[50],lon[50];
    for(i=7,j=0;nmea[i]!=',';i++,j++)
    {
        if(j==2 || j==5)
        {
            time[j]=':';
            i--;
        }
        else
        {
            time[j]=nmea[i];
        }
    }
    time[j]='\0';
    for(i=16,j=0;nmea[i]!=',';i++,j++)
    {
        lat[j]=nmea[i];
    }
    lat[j]='\0';
     for(i=27,j=0;nmea[i]!=',';i++,j++)
    {
        lon[j]=nmea[i];
    }
    lon[j]='\0';
    printf("Time: %s\nLatitude: %s %c\nLongitude: %s %c\n",time,lat,nmea[25],lon,nmea[37]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E