Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *str) {
    // Your logic here
    int i=7,num=0,j=0,k=0;
    char time[20],lat[20],lon[20];
    while(str[i]!='\0'){
      if (i<13) {
          if(j==2) {
           if(i<12) {
            time[k]=':';
             k++;}
          
           j=0;
        }
             time[k]=str[i];
             j++;
             k++;
             if(i==12){
                time[k]='\0';
                k=0;}
        
        
        }
        
    else if (i>=16 && i<=25 ){
        if (str[i]==',') lat[k]=' ';
        else lat[k]=str[i];
        k++;
        if(i==25) {
            lat[k]='\0';
            k=0;}
    }
    else if(i>26){
       if (str[i]==',') lon[k]=' ';
        else lon[k]=str[i];
        k++;
        if(i==38) {
            lon[k]='\0';
            k=0;}
    }
      i++; 
    }
   printf("Time: %s\n",time); 
   printf("Latitude: %s\n",lat);
   printf("Longitude: %s",lon);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E