Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void time(char *nmea, int i)
{
    printf("Time: ");
    for(int x=i;x<i+6;x+=2)
    {
        printf("%c%c",nmea[x],nmea[x+1]);
        if(x!=  i+4)    printf(":");
    }
    printf("\n");

}
void latitude(char *nmea, int i)
{
    printf("Latitude: ");
    for(int x=i;x<=i+10;x++)
    {
        if(nmea[x] == ',')
        {
            printf(" %c",nmea[x+1]); break;
        }
        printf("%c",nmea[x]);
    }
    printf("\n"); 
}
void longitude(char *nmea, int i)
{
    printf("Longitude: ");
    for(int x=i;x<=i+10;x++)
    {
        if(nmea[x] == ',')
        {
            printf(" %c",nmea[x+1]); break;
        }
        printf("%c",nmea[x]);
    }
    printf("\n"); 
}

void parse_gprmc(char *nmea) {
    // Your logic here
    time(nmea, 7);
    latitude(nmea, 16);
    longitude(nmea, 27);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach