Peek N Bytes from Circular Buffer

Code

#include <stdio.h>

typedef struct {
    int buffer[10];
    int head;
    int tail;
    int count;
    int capacity;
} CircularBuffer;

// Write your logic inside this function
void peek_bytes(CircularBuffer *cb, int n) {
    int i;
    int idx;
    int available;
    int cap;

    cap = cb->capacity;      // pointer access
    available = cb->count;   // how many valid items exist
    idx = cb->tail;          // start from tail (do NOT change cb->tail)

    for (i = 0; i < n; i++) {
        if (i < available) {
            printf("%d", cb->buffer[idx]);  // peek value
            idx = (idx + 1) % cap;          // advance locally with wrap-around
        } else {
            printf("NULL");
        }

        if (i != n - 1) {
            printf(" ");
        }
    }
    printf("\n");
}

int main() {
    CircularBuffer cb = {
        .buffer = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100},
        .head = 3,
        .tail = 7,
        .count = 6,
        .capacity = 10
    };

    int n;
    scanf("%d", &n);

    peek_bytes(&cb, n);

    return 0;
}

Solving Approach