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Peek N Bytes from Circular Buffer

Code

#include <stdio.h>

typedef struct {
    int buffer[10];
    int head;
    int tail;
    int count;
    int capacity;
} CircularBuffer;

// Write your logic inside this function
void peek_bytes(CircularBuffer *cb, int n) {
    int x=(*cb).tail;
    int c=0;
    int y=(*cb).count;
    while(c<n){
        int index=x+c;
        if(index>=10){
            index=index-10;
        }
        int d=(*cb).buffer[index];
        c+=1;
        if(c<=y){
        printf("%d",d);
        printf(" ");
        }
        else{
            printf("NULL");
            printf(" ");
        }
    }
}


int main() {
    CircularBuffer cb = {
        .buffer = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100},
        .head = 3,
        .tail = 7,
        .count = 6,
        .capacity = 10
    };

    int n;
    scanf("%d", &n);

    peek_bytes(&cb, n);

    return 0;
}

Solving Approach

 

simple pointer , shifting,structure,looping concepts helped me to solve the problem

 

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Input

4

Expected Output

80 90 100 10