Peek N Bytes from Circular Buffer

Code

#include <stdio.h>

typedef struct {
    int buffer[10];
    int head;
    int tail;
    int count;
    int capacity;
} CircularBuffer;


int peek(CircularBuffer *cb, int pos)
{
    if(pos > cb->count || pos < 1)
    {
        return -1;
    }

    return cb->buffer[(cb->tail + pos-1) % cb->capacity];
}

// Write your logic inside this function
void peek_bytes(CircularBuffer *cb, int n) {
    // Your code here
    for(int i=1; i<=n; i++)
    {
        if(i > cb->count || i < 1)
        {
            printf("NULL ");
        }
        else
        {
            printf("%d ", peek(cb, i));
        }
    }
    
}

int main() {
    CircularBuffer cb = {
        .buffer = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100},
        .head = 3,
        .tail = 7,
        .count = 6,
        .capacity = 10
    };

    int n;
    scanf("%d", &n);

    peek_bytes(&cb, n);

    return 0;
}

Solving Approach