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Peek N Bytes from Circular Buffer

Code

#include <stdio.h>

typedef struct {
    int buffer[10];
    int head;
    int tail;
    int count;
    int capacity;
} CircularBuffer;


void peek_bytes(CircularBuffer *cb, int n) {
    if(cb->count == 0){
        return; 
    }
    
    for(int i = 0; i < n; i++){
        
        if(cb->count == 0){
            if(i == n - 1){
                printf("NULL");
            }
            else{
                printf("NULL ");
            }
        }
        else{
          if(i == n - 1){
             printf("%d", cb->buffer[cb->tail]);
          }
          else{
            printf("%d ", cb->buffer[cb->tail]);
          }
          
          cb->count--; 
          cb->tail = (cb->tail + 1) % cb->capacity;
          
        }
    }
}

int main() {
    CircularBuffer cb = {
        .buffer = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100},
        .head = 3,
        .tail = 7,
        .count = 6,
        .capacity = 10
    };

    int n;
    scanf("%d", &n);

    peek_bytes(&cb, n);

    return 0;
}

Solving Approach

 

Same as the previous problem.

 

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Input

4

Expected Output

80 90 100 10