Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t  result = 0x0;
    for(int i=0;i<8;i++){
        if(reg & (1 << i)){
            int new_pos = (i + n) % 8;
            result |= (1 << new_pos);
        } 
    }
    return result;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach