Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
   // int mask=reg & (n<<8);
   // reg=(reg<<n)|(mask>>(8-n));
   int mask;
   for(int i=1;i<=n;i++){
        mask|=reg & (1<<(8-i));
   }
   reg=(reg<<n) | (mask>>(8-n));
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach