Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t mask = 0x80;
    uint8_t retval = reg;
    for (int i = 0; i < n; i++)
    {
        uint8_t temp_bit = (retval & mask) >> 7;
        retval <<= 1;
        retval |= (temp_bit);

    }
    return retval;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach