Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here     
    for(int j=0; j<n; j++)
    {
        uint8_t temp = (reg&0x80)>>7;
        reg<<=1;
        reg|=temp;
        // printf("reg=%d temp=%d \n",reg,temp);
    }
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach

 

 

 

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Input

176 1

Expected Output

97