Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

void rotate_once(uint8_t *reg){
    int msb=((*reg)>>7)&(1);
    *reg<<=1;
    *reg|=msb;
}
uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    for (int i=0;i<n;i++){
        rotate_once(&reg);
    }
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach