Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    /*
    for (uint8_t i = 0; i < n; i++) {
        if (reg & 0x80) reg = (reg << 1) | 1u;
        else reg <<= 1;
    }
    return reg;
    */
    return (reg << n) | (reg >> (8-n));
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach