Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here

    uint8_t msb;
    
    for (int i = 0; i < n; i++)
    {
        // Extract MSB from reg:
        msb = (reg & 0x80) >> 7;
        
        // Left shift reg by 1;
        reg <<= 1;
        
        // Add the MSB extracted earlier at the place of the LSB of new reg (always 0):
        reg |= msb;
    }

    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach