Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {

    n %= 8;  // ensure n is within 0–7

    // Left shift by n, bring overflowed bits from right
    uint8_t rotated = (reg << n) | (reg >> (8 - n));

    return rotated;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach