Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    if(n==0)return reg;
        uint8_t left=(reg<<n)&0xFF;
        uint8_t wrap= (reg>>(8-n));
        uint8_t result=((left|wrap)& 0xFF); 
        return result;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach