Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>


uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t mask = 0x00;

    //extract the specific value to rotate
    mask |= (reg & ((1 << n) - 1) << 8 - n);

    //shift to left depending in n and mask should shift to desired position 
    reg = (reg << n) | (mask >> (8 - n));

    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach