Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    
    for (uint8_t i = 0; i < n; i++) {
        uint8_t msb = (reg & 0x80) >> 7; // extract bit 7
        reg = (reg << 1) | msb;          // shift left, MSB to LSB
    }
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach