Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
   uint8_t bit;int i;
   uint8_t res;
   int k=n;
   res=reg<<n;
   for(i=1;i<=n;i++){
    bit=(reg>>(8-i))&1;
    res|=bit<<k-1;
    k--;
   }
   res&=0xFF;
    return res;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach