Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t mask = reg >> (8 - n); // FIrst get the bits values from the left most side
    reg = reg << n; //Move the Register by n bits to fill the remaining position on the MSB side
    reg &= ~(n);// Clear the MSB
    reg |= mask;// Fill the MSB with the mask
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach