Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t new_reg = reg;

    uint8_t msb = 0;

    while(n!=0){
        msb = (new_reg & 0x80) >> 7;

        new_reg = new_reg << 1;

        new_reg |= msb;

        n--; 
    }
    return new_reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach