Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    int mask=(1<<n)-1;
    int mask2=0,shift;
    shift=8-n;
    mask=mask<<shift;
    mask=reg & mask;
    mask=mask>>shift;
    reg=reg<<n;
    reg=reg | mask;
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach