Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    int value, mask,res;
    mask = (1<<n)-1; //11 n 2
    value = reg&(mask<<8-n);
    value =value>>8-n;
    reg&=~(mask<<8-n);
    reg = reg<<n;
    res=reg|value;
    return res;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach