Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    n = n%8;
    uint8_t bit = 0;
    uint8_t mask = (uint8_t) 1U << 7;
    for(int i=0; i<n; i++)
    {
         bit = reg & mask;
         reg <<= 1;
         if(bit)
         {
            reg |= 1;
         }
    }

    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach