Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    uint8_t bit=1;
    int i;
    for(i=0;i<n;i++){
    if(((reg>>8) & bit)==1)
    {
    reg = (reg>>1);
    reg+= 1<<7;
    }
    else{
    reg = reg>>1;
    reg += 0<<7;
    }
  }
    return reg;
}

int main() {
    uint32_t reg;
    uint8_t n;
    scanf("%u %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach