Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    n %= 8;
    if(n == 0){return reg;}

    uint8_t mask = (((1 << n) - 1) << (8 - n));
    uint8_t temp = (reg & mask) >> (8 - n);

    reg <<= n;
    reg |= temp;

    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach