Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t mask=(((1U<<n)-1)<<(8-n));
    mask&=reg;
    mask>>=(8-n);
    reg&=(~(((1U<<n)-1)<<(8-n)));
    reg<<=n;
    reg&=(~((1U<<n)-1));
    reg|=mask;
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach