Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t reg1=0;
    n=n%8;
    if (n==0){
        return reg;
    }
    for (int i=7;i>7-n;i--){
        reg1|=(((reg>>i) & 1)<<(i-8+n));
    }
    reg=(reg<<n) | reg1;
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach