Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    //extract the n bits from MSB
    // uint8_t extract_val = (reg >>(8 - n)); // n=1 -> 7
    // reg <<= n;
    // uint8_t mask = ((1<<n) -1);
    // reg &= ~mask;
    // reg |= extract_val;   
    return ((reg << n) | reg >> (8 - n));
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

176 1

Expected Output

97