Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t result;
    for(int i=0;i<8;i++){
        if(reg & (1<<i)){
            if((i+n) < 8){
                result |= (1<<(i+n));
            }else{
                result |= (1<<((i+n)-8));
            }
        }
    }
    return result;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach