Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) 
{
     int arr[8],num=0;
    for(int i=0;i<8;i++)
    {
        arr[i]=(reg>>i)&1;
    }
    while(n)
    {
        int temp=arr[7];
        for(int i=6;i>=0;i--)
        {
            arr[i+1]=arr[i];
        }
        arr[0]=temp;
        n--;
    }
    for(int i=7;i>=0;i--)
    {
        if(arr[i]==1)
        {
            num |=1<<i;
        }
        else
        {
            num&=~(1<<i);
        }
    }
    return num;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach