Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    uint8_t b=0,a=0;
    int c=0;
    for(int i=8-n;i<8;i++){
       a=1&(reg>>i);
        b=b|(a<<c);
        c++;
    }
    reg=(reg<<n)|b;
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach