Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    uint8_t bitToShift = 0;
    for(int i = 0; i<n; i++)
    {
        bitToShift = reg>>7; //Get bit to be shifted, to the position 0;
        reg = (reg<<1)|(bitToShift<<0); //shift reg by 1 position to the left and add bitToShift
    }
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach