Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t ans = (reg<<n) | (reg>>(7-(n-1)));
    return ans;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

// Rotate Left
// ABCD EFGH
// n=3
// [ABC][DEFGH]
// [DEFGH] [ABC]

Solving Approach