Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    for(uint8_t x = 1;x<=n;x++)
    {
        uint8_t cap_bit = reg & 0x80;
        cap_bit>>= 7;
        reg<<= 1;
        reg&= 0xfe;
        reg|= cap_bit;
    }
    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach