Rotate Left in an 8-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t rotate_left(uint8_t reg, uint8_t n) {
    // Your code here
    uint8_t temp_reg = reg >> (8 -n);
    uint8_t mask = 1;

    for(uint8_t i = 0; i<n-1;++i)
    {
        mask |= (mask << 1);
    }

    reg <<= n;
    reg &= ~(mask);
    reg |= temp_reg;

    return reg;
}

int main() {
    uint8_t reg, n;
    scanf("%hhu %hhu", &reg, &n);
    printf("%u", rotate_left(reg, n));
    return 0;
}

Solving Approach