#include <iostream>
#include <string>
class Buffer {
private:
int id;
public:
Buffer(int i) : id(i) {}
// Standard signature for copy assignment operator
Buffer& operator=(const Buffer& other) {
// Step 1: Self-assignment check
// 'this' is a pointer to the current object.
// '&other' is the address of the source object.
if (this == &other) {
std::cout << "Self-Assignment Detected" << std::endl;
// Return current object immediately, do NOT modify anything
return *this;
}
// Step 2: Normal assignment logic
id = other.id;
std::cout << "Assignment Complete" << std::endl;
// Step 3: Return reference to support chaining (a = b = c)
return *this;
}
void log() {
std::cout << "Buffer ID: " << id << std::endl;
}
};
int main() {
int N;
if (!(std::cin >> N)) return 0;
for (int i = 0; i < N; ++i) {
std::string cmd;
std::cin >> cmd;
if (cmd == "ASSIGN") {
int i1, i2;
std::cin >> i1 >> i2;
Buffer b1(i1);
Buffer b2(i2);
b1 = b2;
b1.log();
} else if (cmd == "SELF") {
int i1;
std::cin >> i1;
Buffer b1(i1);
b1 = b1; // This triggers the self-assignment check
b1.log();
}
}
return 0;
}Explanation & Logic Summary:
this holds the memory address of the object on the left side of the = sign. &other holds the address of the object on the right side. If these addresses are equal, they are the same physical object in memory.*this? C++ allows chaining assignments: a = b = c. The expression b = c must evaluate to a reference to b so that a can copy from it.Firmware Relevance & Real-World Context:
dma1 = dma1, a naive implementation might "Stop and Release" the channel before "Acquiring" it. Since it's the same object, you've just released the channel you were trying to use, causing a hard crash. The if (this == &other) check prevents this catastrophe.
Input
2 ASSIGN 10 20 SELF 99
Expected Output
Assignment Complete Buffer ID: 20 Self-Assignment Detected Buffer ID: 99