18. Set Multiple Bits in 8-bit Register

You are given an 8-bit register. Set all bits between position start and end (inclusive).

Use 0-based indexing and assume start <= end.


Example 1

Input: reg = 0b00000000, start = 1, end = 3 
Output: 0b00001110

Example 2

Input: reg = 0b00001000, start = 0, end = 2 
Output: 0b00001111

Example 3

Input: reg = 0b00000001, start = 3, end = 5 
Output: 0b00111001

 

 


 

Need Help? Refer to the Quick Guide below

In embedded systems, a single register often contains multiple fields, each controlling a different function. These fields are packed into specific bit positions.

Example: A 16-bit Control Register

BitsField Name
15 – 12Mode
11 – 8Speed
7 – 0Flags

To work with them, we need two core skills:

  1. Extracting a field (reading the bits at a specific position)
  2. Replacing or updating that field (without touching other bits)
     

This is done using bit masking and bit shifting.

To extract Speed field (bits 8 to 11):

uint16_t speed = (reg >> 8) & 0x0F;

To update the Mode field (bits 12 to 15):

reg &= ~(0x0F << 12);         // Clear Mode bits
reg |= ((new_mode & 0x0F) << 12); // Set new Mode

Key Operations

Extract a bit field

value = (reg >> position) & mask;

Replace a bit field

/* Where mask is a binary mask for the number of bits in the field.
E.g., For 3-bit field → mask = 0x07 */


reg &= ~(mask << position);            // Clear the bits (mask= high bits)
reg |= ((new_value & mask) << position); // Set the new bits

Relevance in Embedded/Firmware

  • Most hardware registers (UART, Timer, ADC, SPI) use bit fields to define different parameters.
  • Peripheral setup often involves:
    • Extracting status bits (e.g., data ready, error)
    • Modifying specific bits (e.g., set baud rate, enable TX)
  • It’s unsafe to overwrite the entire register — instead, we update only the target bits.

This is why precise extraction and modification using bit masks is a core embedded skill.