Question.3
A developer writes a function to compute the number of elements in a sensor buffer:
void process(int buf[]) {
int count = sizeof(buf) / sizeof(buf[0]);
printf("Elements: %d", count);
}
int main() {
int readings[10] = {0};
process(readings);
}On a 32-bit platform where sizeof(int) = 4 and sizeof(int*) = 4, what does this print?
An array in C is a contiguous block of memory that stores multiple elements of the same data type. It allows you to:
Array Declaration
int numbers[10]; // Array of 10 integers
uint8_t buffer[32]; // 32-byte buffer (commonly used in firmware)
Declares a fixed-size array — memory is allocated statically.
Array Initialization
int values[4] = {10, 20, 30, 40}; // full initialization
int empty[4] = {0}; // all elements = 0
char message[] = "Hi"; // string-style initIf you skip the size (like message[ ]) , the compiler counts the size automatically.
Accessing Array Elements
int arr[3] = {5, 10, 15};
printf("%d", arr[1]); // prints 10
arr[2] = 20; // modify element at index 2The index starts from 0. Always ensure you stay within 0 to n-1.
Array Size with sizeof()
int arr[5];
int total_bytes = sizeof(arr); // e.g., 20 if int = 4 bytes
int element_bytes = sizeof(arr[0]); // gives size of int i.e. 4 bytes
int element_count = sizeof(arr) / sizeof(arr[0]); // gives 5This only works within the same scope where the array is declared (not when passed to a function).
int arr[4] = {10, 20, 30, 40};
Assuming the starting address is 0x2000, the memory looks like:
| Address | Value |
|---|---|
| 0x2000 | 10 |
| 0x2004 | 20 |
| 0x2008 | 30 |
| 0x200C | 40 |
Each int = 4 bytes (on most systems).
In embedded systems, arrays are used for: