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69. Binary Subtractor

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Solving Approach

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Code

/*Write your code here*/
module sub4_2c(input [3:0]a,b,output [3:0]diff,output bout);
wire cout;
       // Width-safe 5-bit add to capture carry-out
    wire [4:0] sum5 = {1'b0, a} + {1'b0, ~b} + 5'b00001;
    assign diff = sum5[3:0];
    assign bout = ~sum5[4]; // borrow = NOT carry-out
      
endmodule

 

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