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69. Binary Subtractor

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Solving Approach

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Code

/*Write your code here*/
module sub4_2c(
    input [3:0] a, b,
    output [3:0] diff,
    output bout
);
    wire [4:0] sum = {1'b0, a} + {1'b0, ~b} + 5'b00001;
    assign diff = sum[3:0];
    assign bout = ~sum[4];
endmodule

 

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