19. Extract a Bit Field from a 32-bit Register
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JAbisek
Sep 16 2026
#include <stdio.h>
#include <stdint.h>
uint32_t extract_field(uint32_t reg, uint8_t pos, uint8_t len) {
// Your code here
uint32_t res=0;
reg>>=pos;
reg<<=(32-len);
reg>>=(32-len);
return reg;
}
int main() {
uint32_t reg;
uint8_t pos, len;
scanf("%u %hhu %hhu", ®, &pos, &len);
printf("%u", extract_field(reg, pos, len));
return 0;
}
0
78rsingh87
Jul 26 2026
Case 1 and case 5 both have the same position and length specification. They solution behaves differently. What didn't I understand about the question?
0
#include <stdio.h>
#include <stdint.h>
uint32_t extract_field(uint32_t reg, uint8_t pos, uint8_t len) {
reg = reg >> pos; // ex 8 bit 1011 0010 --> 0000 1011 : pos 4 , len 3
reg = reg << (32 - len); // 0110 0000 (8 - 3) <<5
reg = reg >> (32 - len);// 0000 0110 >>5
return reg;
}
int main() {
uint32_t reg;
uint8_t pos, len;
scanf("%u %hhu %hhu", ®, &pos, &len);
printf("%u", extract_field(reg, pos, len));
return 0;
}