Extract a Bit Field from a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t extract_field(uint32_t reg, uint8_t pos, uint8_t len) {
    // Your code here
    unsigned int newreg=(reg>>pos);
    //printf("%ud",newreg);
    int end=len;
    //printf("%d\n",end);
    for (end;end<=31;end++){
        newreg&=~(1<<end);
        //printf("%u\n",newreg);
    }
    return newreg;
}

int main() {
    uint32_t reg;
    uint8_t pos, len;
    scanf("%u %hhu %hhu", &reg, &pos, &len);
    printf("%u", extract_field(reg, pos, len));
    return 0;
}

Solving Approach

First right shift the reg to the start point and then erase the bits after len

 

 

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Input

3060793344 28 4

Expected Output

11