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From the behavioral table, the circuit must generate AND, OR, and NOT A outputs using only NAND gates.
| A | B | AND Output | OR Output | NOT A Output |
|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 1 |
| 0 | 1 | 0 | 1 | 1 |
| 1 | 0 | 0 | 1 | 0 |
| 1 | 1 | 1 | 1 | 0 |
AND, OR, NOT, NOR, XOR, and XNOR gates are prohibited. Only NAND gates can be used.
Required:
Y = A'Using the Boolean law:
A · A = ATherefore:
Y = (A · A)'So, connect A to both inputs of a NAND gate.
Required:
Y = A · BApply double inversion:
Y = (A · B)'' // By law A'' = AAssume:
Z = (A · B)' // First NAND gateThen:
Y = Z'From Step 1, NOT can be implemented using NAND:
Y = (Z · Z)'Therefore:
AND Output = ((A · B)' · (A · B)')'Required:
Y = A + BUsing De Morgan's theorem:
Y = (A' · B')'From Step 1:
A' = (A · A)'
B' = (B · B)'Substituting:
OR Output = ((A · A)' · (B · B)')'Now the three functions can be implemented as:
| Required Function | NAND Implementation |
|---|---|
| NOT A | (A · A)' |
| AND | ((A · B)' · (A · B)')' |
| OR | ((A · A)' · (B · B)')' |
Connect the NAND gates according to these derived expressions to generate all three outputs.